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If 60% of a first order reaction was com...

If 60% of a first order reaction was completed in 60 minutes, 50% of the same reaction would be completed in approximately (log 4 = 0.60 log 5 = 0.69)

A

`50` min

B

`45` min

C

`60` min

D

`40` min

Text Solution

Verified by Experts

The correct Answer is:
B
`k=(2.303)/(60)log.(100)/(40)implies0.152`
`k=(0.693)/(T_(1//2))impliesT_(1//2)=(0.693)/(0.152)=45.37` min
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