The rate constant for a chemical recation has units `L"mol"^(-1)s^(-1)` , order of the reaction will be

Options

A. 0
B. 1
C. 2
D. 3

Explanation

To determine the order of a reaction given the units of the rate constant, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Units of the Rate Constant**:
The units of the rate constant (k) are given as \( L \cdot mol^{-1} \cdot s^{-1} \).

2. **Write the General Expression for the Rate Constant**:
For a reaction of order \( n \), the units of the rate constant can be expressed as:
\[ k = \frac{mol}{L} \cdot L^{(1-n)} \cdot s^{-1} \]
Here, \( L^{(1-n)} \) accounts for the concentration term raised to the power of \( (1-n) \).

3. **Simplify the Expression**:
Rearranging the expression, we have:
\[ k = \frac{mol}{L} \cdot L^{(1-n)} \cdot s^{-1} = \frac{mol \cdot L^{(1-n)}}{L \cdot s} \]
This can be further simplified to:
\[ k = \frac{mol \cdot L^{(1-n-1)}}{s} = \frac{mol \cdot L^{(-n)}}{s} \]

4. **Set the Units Equal**:
Now we equate the units we derived for \( k \) with the given units \( L \cdot mol^{-1} \cdot s^{-1} \):
\[ \frac{mol \cdot L^{-n}}{s} = L \cdot mol^{-1} \cdot s^{-1} \]

5. **Compare the Exponents**:
From the left side, we have:
- The exponent of \( mol \) is \( 1 \) (from \( mol \)) and \( -1 \) (from \( mol^{-1} \)), giving \( 1 - 1 = 0 \).
- The exponent of \( L \) is \( -n \) from the left side and \( 1 \) from the right side.

Therefore, we can set up the equation:
\[ -n = 1 \]
Solving for \( n \):
\[ n = -1 \]

6. **Find the Order of Reaction**:
The order of the reaction is:
\[ n = 2 \]

### Conclusion:
The order of the reaction is **2**.