The following data are for the decomposition of ammonium nitrite in aqueous solution.:
`{:("Vol of" N_(2)(cm^(3)),6.25,9.0,11.42,13.65,35.2),("Time (min)",10,15,20,25,oo):}`
The order of reaction is :

Options

A. Zero
B. One
C. Two
D. Three

Answer

B

Explanation

`{:("Ammonium",,N_(2)("inC.C"),,"Time min"),("nitrate",,,,),(a,,0,,0),(a-x_(1),,x_(1)=6.25,,10),(a-x_(2),,x_(2)=9.50,,15),(a-x_(3),,x_(3)=11.42,,20),(a-x_(4),,x_(4)=13.65,,25),(a-a,,a=35.05,,"Finally"):}`
For first order reaction
`k=(2.303)/(t)log.(a)/(a-x)` should be constant
at `t=10` min , `k=(2.303)/(10)log.(35.05)/(35.05-6.25)=0.02`
at `t=15` min. , `k=(2.303)/(15)log.(35.05)/(35.05-9.5)=0.02`
at `t=20` min. , `k=(2.303)/(20)log.(35.05)/(35.05-11.42)=0.02`
at `t=25` min., `k=(2.303)/(25)log.(35.05)/(35.05-13.65)=0.02`
So this is a first order reaction .