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Cyclopropane rearranges to form propane ...

Cyclopropane rearranges to form propane :
`DeltararrCH_(3)-CH=CH_(2)`
This follows first order kinetics. The rate constant is `2.174xx10^(-3) "sec"^(-1)` . The initial concentration of cyclopropane is `0.29 M` . What will be the concentration of cyclopropane after 100 sec

A

`0.035` M

B

`0.22` M

C

`0.145` M

D

`0.0018` M

Text Solution

Verified by Experts

The correct Answer is:
B
`k=(2.303)/(t)log.(a)/((a-x))`
`(a-x)` is the concentration left after `100` s .
`2.7xx10^(-3)=(2.303)/(100)log.(0.29)/((a-x))`
implies `(0.27)/(2.303)=log.(0.29)/((a-x))implies0.117=log.(0.29)/((a-x))`
implies `(a-x)=0.22` M .
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