For the second order reaction,
`A+Brarr"products"`
when a moles of A react with b moles of B, the rate equation is given by
`k_(2)t=(1)/(a-b)In(b(a-x))/(a(b-x))`
when `agtgtb,` the rate expression becomes that of

Options

A. First order
B. Zero order
C. Unchanged , second order
D. Third order

Answer

A

Explanation

`k_(2)t=(1)/((a-b))ln.(b(a-x))/(a(b-x))`
`agtgtb` means `(a-x)~~a` and `(a-b)~~a`
i.e., `k_(2)t=(1)/(a)ln.(ba)/(a(b-x))impliesk_(2)t=(1)/(a)ln.(b)/((b-x))`
( Since .a. being very large, may be treated as constant after the change . ) Thus, the reaction follows first order kinetics .