The rate of the reaction `A rarr` products, at the initial concentration of `3.24 xx 10^(-2)M` is nine times its rate at another initial concentration of `1.2 xx 10^(-3)M`. The order of reaction is

Options

A. `(1)/(2)`
B. `(3)/(4)`
C. `(3)/(2)`
D. `(2)/(3)`

Answer

D

Explanation

`9r=k(3.24xx10^(-2))^(alpha)` ….(i)
`r=k(1.2xx10^(-3))^(alpha)` ….(ii)
Divide eqn. (i) by (ii)
`(9r)/(r)=(k(3.24xx10^(-2))^(alpha))/(k(1.2xx10^(-3))^(alpha))implies3^(2)=3^(3alpha)`
:. `alpha=(2)/(3)`