Which one of the following is wrongly matched

Options

A. Saponification of `CH_(3)COOC_(2)H_(5)` - Second order reaction
B. Hydrolysis of `CH_(3)COOCH_(3)` - Pseudo uni-molecular reaction
C. Decomposition of `H_(2)O_(2)` - First order reaction
D. Combination of `H_(2)` and `Br_(2)` to give HBr- Zero order reaction

Answer

D

Explanation

`H_(2)+Br_(2)hArr2HBr` is a `1.5` order reaction
i.e., `k=[H_(2)][Br_(2)]^(1//2)`