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The following graph shows how t(1//2) (h...

The following graph shows how `t_(1//2)` (half-life) of a reactant R changes with the initial reactant concentration `a_(0)`.
The order of reaction will be

A

0

B

1

C

2

D

3

Text Solution

Verified by Experts

The correct Answer is:
C

`t_(1//2)prop(1)/(a_(0)^(n-1))`
`a_(0)^(n-1)=a_(0)` (given)
:. `n-1=1impliesn=2`
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