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For a first order reaction A to product...

For a first order reaction `A to ` product the rate of reaction at [A] = `0.2 mol l^(-1)` is `1.0 xx 10^(-2) "min"^(-1)` . The half life period for the reaction is

A

`832`s

B

`440` s

C

`416` s

D

`13.86` s

Text Solution

Verified by Experts

The correct Answer is:
A
r=k[reactant]
:. `k=(1.0xx10^(-2))/(0.2)=0.05`
`t_(1//2)=(0.693)/(0.05)=13.86"min"=13.86xx60=831.6s`
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