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After how many seconds will the concentr...

After how many seconds will the concentration of the reactant in a first order reaction be halved if the rate constant is `1.155xx10^(-3)s^(-1)`?

A

`100` s

B

`200` s

C

`400` s

D

`600` s

Text Solution

Verified by Experts

The correct Answer is:
D
`t=(2.303)/(k)log.(a)/(a-x)`
`t=(2.303)/(1.155xx10^(-3))log.(100)/(100-50)=600` s
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