The rate constant fro a second order reaction is `8 xx 10^(-5) M^(-1) "min"^(-1)`. How long will in take a `1 M` solution to be reduced to `0.5 M`

Options

A. `8xx10^(-5)` min
B. `8.665xx10^(3)` min
C. `4xx10^(-5)` min
D. `1.25xx10^(4)` min

Answer

D

Explanation

`8xx10^(-5)=(1)/(t)[(1)/(0.5)-(1)/(1)]`
implies `8xx10^(-5)=(1)/(t)(2-1)`
`t=(1)/(8xx10^(-5))=0.125xx10^(5)=1.25xx10^(4)"min"`