After 2 hours the amount of a certain radioactive substance reduces to `1//16^(th)` of the original amount (the decay process follows first-order kinetics). The half-life of the radioactive substance is

Options

A. 15 min
B. 30 min
C. 45 min
D. 60 min

Answer

B

Explanation

`(0.693)/(t_(1//2))=(2.303)/(2xx60)log.(a)/(a//16)`
`t_(1//2)=30` min