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If the activation enery for the forward ...

If the activation enery for the forward reaction is `150 "kJ mol"^(-1)` and that of the reverse reaction is `260 "kJ mol"^(-1)`. What is the ethalpy change for the reaction ?

A

`410"kJ mol"^(-1)`

B

`-110"Kj mol"^(-1)`

C

`110 "kJ mol"^(-1)`

D

`-410 "kJ mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
For a reversible recation, `DeltaH=E_(a)` (forward) `-E_(a)` (backward)
`DeltaH=150-260=-110"kJ mol"^(-1)`
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