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The rate constant (K') of one reaction i...

The rate constant `(K')` of one reaction is double of the rate constant (K") of another reaction. Then the relationship between the corresponding activation energies of the two reactions `(E_(a)^(') "and" E_(a)^(''))` will be

A

`E_(a)gtE_(a)`

B

`E_(a)=E_(a)`

C

`E_(a)ltE_(a)`

D

`E_(a)=4E_(a)`

Text Solution

Verified by Experts

The correct Answer is:
C
As `Kgt K, E_(a) lt E_(a)`
(Greater the rate constant, less is the activation energy ) .
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