Home
Class 12
CHEMISTRY
A chemical reaction was carried out at 3...

A chemical reaction was carried out at 300 K and 280 K. The rate constants were found to be `k_(1) and k_(2)` respectively. Then

A

`K_(2)~~0.25K_(1)`

B

`K_(2)~~0.5K_(1)`

C

`K_(2)~~4K_(1)`

D

`K_(2)~~2K_(1)`

Text Solution

Verified by Experts

The correct Answer is:
A
The value of the rate constant will be double for every 10 K rise in temperature.
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    ERRORLESS|Exercise NCERT BASED QUESTIONS (Photochemical Reaction)|4 Videos

  • CHEMICAL KINETICS

    ERRORLESS|Exercise NCERT BASED QUESTIONS (Graphical Questions)|7 Videos

  • CHEMICAL KINETICS

    ERRORLESS|Exercise NCERT BASED QUESTIONS (Rate Law and Rate Constant)|106 Videos

  • CARBOXYLIC ACIDS

    ERRORLESS|Exercise Assertion & Reason|5 Videos

  • CHEMISTRY IN EVERYDAY LIFE

    ERRORLESS|Exercise Assertion & Reason|4 Videos

Similar Questions

Explore conceptually related problems

the hydrolysis of ethyl acetate was carried out separately with 0.05 MHCI and 0.05 M H_(2) SO_(4) .The rate constants were found to be K_(1) and K_(2) respectively . Then

Hydrolysis of amyl acetate was carried out separately in the presence of 0.02 M HCl and 0.02 M H_(2)SO_(4) The rate constants were found to be k_(1) and k_(2) then

Two reactions R_(2) and R_(2) have identical pre - exponential factors. Activations enery of R_(1) exceeds that of R_(2) by 10 kJ mol_(-1) . If k_(1) and k_(2) are rate constants for rate constants for reactions R_(1) and R_(2) respectively at 300k , then In (k_(2)/k_(1)) is equal to (R=8.314 J mol^(-1)K^(-1))

A reaction takes place in various steps. The rate constant for first, second, third and fifth steps are k1, k2, k3 and k5 respectively. The overall rate constant is is given by: k = k_(2)/k_(1) (k_(1)/k_(2))^(1/2) activation energy are 40,60, 50 and 10 kJ/mol respectively, find the overall energy of activation (kJ/mol).

Two different first order reaction have rate constants k_1 and k_2 at T_1(k_1 gt k_2) > If temperature is increased from T_1 " to " T_2 . Then new constants become k_3 and k_4 respectively. Which among the following relations is correct /

A reaction takes place in three rate determining steps having rate constants K_(1), K_(2), K_(3) respectively. The overall rate constant K=(K_(1)K_(3))/K_(2) . If energy of activations for the three steps are respectively 10, 20, 40 kJ . The overall energy of activation is:

ERRORLESS-CHEMICAL KINETICS-NCERT BASED QUESTIONS (Collision Theory, Energy of Activation and Arrhenius Equation)
  1. Which of the following statements is incorrect about the collision the...

    Text Solution

    |

  2. Which of the following statement is not correct for the catalyst ...

    Text Solution

    |

  3. A chemical reaction was carried out at 300 K and 280 K. The rate const...

    Text Solution

    |

  4. Transition state 2 (T.S.2) is structurally most likely as

    Text Solution

    |

  5. Which graph shows zero activation energy ?

    Text Solution

    |

  6. If a homogeneous catalytic reaction can take place through three alter...

    Text Solution

    |

  7. In Arrhenius plot, intercept is equal to

    Text Solution

    |

  8. ARRHENIUS THEORY

    Text Solution

    |

  9. The Arrhenius equation expressing the effect of temperature on the rat...

    Text Solution

    |

  10. The rate constant of a reaction at temperature 200 K is 10 times less ...

    Text Solution

    |

  11. In respect of the equation k=Ae^(-E(a)//RT) in chemical kinetics, whic...

    Text Solution

    |

  12. Activation energy (E(a)) and rate constants (k(1) and k(2)) of a chemi...

    Text Solution

    |

  13. The specific rate constant for a reaction increases by a factor of 4, ...

    Text Solution

    |

  14. The rate temperature changes from 300K to 310K. Activation energy of s...

    Text Solution

    |

  15. The activation energy of a reaction can be determined from the slope o...

    Text Solution

    |

  16. The temperature dependence of rate constant (k) of a chemical reaction...

    Text Solution

    |

  17. A reaction rate constant is given by k = 1.2 xx 10^(14) e^((-2500)/(...

    Text Solution

    |

  18. In the Arrhenius plot of ln k vs (1)/(T) , a linear plot is obtained w...

    Text Solution

    |

  19. For a reaction taking place in three steps, the rate consatnt are k(1)...

    Text Solution

    |

  20. A graph plotted between log k versus 1//T for calculating activation e...

    Text Solution

    |