The specific rate constant for a reaction increases by a factor of 4, if the temperature is changed from `27^(@)C" to "47^(@)C`. Find the activation energy for the reaction.

Options

A. 2
B. 40
C. e
D. `e^(2)`

Answer

C

Explanation

`ln.(K_(2))/(K_(1))=(E_(a))/(R)((1)/(T_(1))-(1)/(T_(2)))` or
`impliesln.(K_(2))/(K_(1))=(600R)/(R)((1)/(300)-(1)/(600))`
or, `ln.(K_(2))/(K_(1))=(600R)/(R)((2-1)/(600))=1`
`ln.(K_(2))/(K_(1))=lneimplies(K_(2))/(K_(1))=e`