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A graph plotted between log k versus 1//...

A graph plotted between `log k` versus `1//T` for calculating activation energy is shown by

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B

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The correct Answer is:
B
A graph plotted between `log K Vs. (1)/(T)` for calculating activation energy is shown as from Arrhenius equation `logK=logA-(E_(A))/(2.303RT)`
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