Following equation gives variation of equilibrium constant k with temperature T
`logk=logA-(DeltaH)/(2.303RT)`
Graphically this variation is represented as

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Explanation

To solve the problem regarding the variation of the equilibrium constant \( k \) with temperature \( T \), we start from the given equation:

\[ \log k = \log A - \frac{\Delta H}{2.303RT} \]

### Step 1: Identify the Variables
In the equation, we can identify:
- \( \log k \) as the dependent variable (Y-axis)
- \( \frac{1}{T} \) as the independent variable (X-axis)
- \( \log A \) as the y-intercept
- \( -\frac{\Delta H}{2.303R} \) as the slope of the line

### Step 2: Rearranging the Equation
We can rearrange the equation in the form of \( Y = mx + c \):
\[ \log k = -\frac{\Delta H}{2.303R} \cdot \left(\frac{1}{T}\right) + \log A \]
Here, \( Y = \log k \), \( x = \frac{1}{T} \), \( m = -\frac{\Delta H}{2.303R} \), and \( c = \log A \).

### Step 3: Analyzing the Slope
The slope \( m \) is negative, which indicates that as \( \frac{1}{T} \) increases (meaning temperature \( T \) decreases), \( \log k \) decreases. This suggests an inverse relationship between \( k \) and \( T \).

### Step 4: Graphical Representation
When we plot \( \log k \) on the Y-axis against \( \frac{1}{T} \) on the X-axis, we will get a straight line with a negative slope. The line will intercept the Y-axis at \( \log A \).

### Conclusion
The graphical representation of the variation of the equilibrium constant \( k \) with temperature \( T \) is a straight line with a negative slope.

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