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The bromination of acetone that occurs i...

The bromination of acetone that occurs in acid solution is represented by
`CH_(3)COCH_(3)(aq.)+Br_(2)(aq.)rarrCH_(3)COCH_(2)Br(aq.)+H^(+)(aq.)+Br^(-)(aq.)`
These kinetic data were obtained for given reaction concentrations :

Based on these data, rate equations is :

A

Rate `=k[CH_(3)COCH_(3)][Br_(2)][H^(+)]^(2)`

B

Rate `=k[CH_(3)COCH_(3)][Br_(2)][H^(+)]^(2)`

C

Rate `=k[CH_(3)COCH_(3)][H^(+)]`

D

Rate `=k[CH=COCH_(3)][Br_(2)]`

Text Solution

Verified by Experts

The correct Answer is:
C

From experiment (i) and (ii), rate doesn.t depend on the concentration of `Br_(2)`. So , rate expression will not include `[Br_(2)]`.
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The bromination of acetone that occurs in acid solution is represented by this equation. CH_(3)COCH_(3) (aq) + Br_(2) (aq) rarr CH_(3)COCH_(2) Br(aq) + H^(+) (aq) + Br(aq) These kinetic data were obtained for given reaction concentrations. Initial concentration, M {:([CH_(2)COCH_(3)],[Br_(2)],[H^(+)],("Initail rate) (disappearance of "Br_(2)),),(0.30,0.05,0.05,1.5 xx 10^(-5),),(0.30,0.10,0.05,5.7xx10^(-5),),(0.30,0.10,0.10,1.2xx10^(-4),),(0.40,0.5,0.20,3.1xx10^(-4),):}

For the reaction : (CH_(3))_(3)CBr(aq)+OH^(-)(aq)rarr(CH_(3))_(3)COH(aq)+Br^(-)(aq) it is found that halving the concentration of (CH_(3))_(3)CBr causes the reaction rate to be halved but halving the concentration of OH^(-) has no effect on the rate. What is the rate law?

Consider the reaction: H_(2)SO_(3)(aq)+Sn^(4+)(aq)+H_(2)O(l)toSn^(2+)(aq)+HSO_(4)^(-)(aq)+3H^(+)(aq) Which of the following statements is correct?

Assertion :- Bromide ion is serving as a reducing agent in the reaction 2MnO_(4)^(-)(aq.)+Br^(-)(aq.)+H_(2)Orarr2MnO_(2)(aq.)+BrO_(3)^(-)(aq.)+2OH^(-)(aq.) Reason :- Oxidation number of Br increases from -1 to +5

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