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The decomposition of phosphine [PH(3)] o...

The decomposition of phosphine `[PH_(3)]` on tungsten at low pressure is a first-order reaction. It is because the

A

Rate of decomposition is very slow

B

Rate is proportional to the surface coverage

C

Rate is inversely proportional to the surface coverage

D

Rate is independent of the surface coverage

Text Solution

Verified by Experts

The correct Answer is:
B
`PH_(3)overset(W)(to)P+(3)/(2)H_(2)`
Rate `=k[PH_(3)]`
It is dependent of the surface coverage because first order reaction depends on surface area covered by reactant
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