The slope of Arrhenius plot `(l_(n)k " vs " 1//T)` of a first order reaction is `-5 xx 10^(3)`. The value of `E_(a)` of the reaction is `(R = 8.314 J K^(-1)mol^(-1))`

Options

A. `83.0kJmol^(-1)`
B. `166kJmol^(-1)`
C. `-83kJmol^(-1)`
D. `41.5kJmol^(-1)`

Answer

D

Explanation

`lnk=(-E_(a))/(RT)+lnA`
Slope=`(-E_(a))/(R)`
`-5xx10^(3)=(-E_(a))/(R)`
`E_(a)=5xx10^(3)xxR`
`=5xx10^(3)xx8.314`
`=41.57xx10^(3)` J`mol^(-1)`
`=41.57kJmol^(-1)`