The coagulation of 200 mL of a positive sol took place when 0.73 g HCl was added to it without changing the volume much. The flocculation value of HCl for the colloid is :

Options

A. 0.365
B. 36.5
C. 100
D. 150

Answer

C

Explanation

200 mL of sol needs = `(0.73g)/(36.5g//mol) = 0.02mol`
= 20 m mol
1000 mL of the sol will need = `(20xx1000)/(200) = 100 m mol`
`therefore` value of HCl for colloid is 100.