The IUPAC name of `[Ni(CO)_4]` is

Options

A. Tetra carbonyl nickel (II)
B. Tetra carbonyl nickel (0)
C. Tetra carbonyl nickelate (II)
D. Tetra carbonyl nickelate (0)

Explanation

To determine the IUPAC name of the coordination compound \([Ni(CO)_4]\), we can follow these steps:

### Step 1: Identify the central metal atom and its oxidation state.
- The central metal atom in this complex is Nickel (Ni).
- The ligand present is Carbon monoxide (CO), which is a neutral ligand (it has no charge).
- Since the overall charge of the complex is neutral (0), the oxidation state of Nickel can be calculated as follows:
\[ \text{Oxidation state of Ni} + \text{(number of CO ligands)} \times \text{(charge of CO)} = 0 \]
\[ X + 4 \times 0 = 0 \implies X = 0 \]
- Therefore, the oxidation state of Nickel in this complex is 0.

### Step 2: Identify the ligands and their prefixes.
- The ligand in this complex is Carbon monoxide (CO).
- Since there are four CO ligands, we use the prefix "tetra-" to indicate the number of ligands.

### Step 3: Combine the ligand name with the metal name and oxidation state.
- The name of the ligand (CO) is "carbonyl."
- The name of the metal (Nickel) remains the same.
- Since the oxidation state of Nickel is 0, we denote this as "nickel(0)."

### Step 4: Write the complete IUPAC name.
- Combining all the information, the IUPAC name of the compound \([Ni(CO)_4]\) is:
\[ \text{Tetra carbonyl nickel(0)} \]

### Final Answer:
The IUPAC name of \([Ni(CO)_4]\) is **Tetra carbonyl nickel(0)**.

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