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A solution containing 2.675 g of CoCl(3)...

A solution containing 2.675 g of `CoCl_(3).6NH_(3)` (molar mass = 267.5 g `mol^(-1)` is passed through a cation exchanger. The chloride ions obtained in solution are treated with excess of `AgNO_(3)` to give 4.78 g of AgCl (molar mass = 143.5 g `mol^(-1)` ). The formula of the complex is (At.mass of Ag = 108 u ) .

A

`[CoCl(NH_3)_5]Cl_2`

B

`[Co(NH_3)_6]Cl_3`

C

`[CoCl_2(NH_3)_4]Cl`

D

`[CoCl_3(NH_3)_3]`

Text Solution

Verified by Experts

The correct Answer is:
B
`[Co(NH_3)_6]Cl_3`
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A solution containing 2.675 g of CoCl_(3).6NH_(3) (molar mass = 267.5 g mol^(-1) ) is passed through a cation exchanger. The chloride ions obtained is solution were treated with excess of AgNO_(3) to give 4.73 g of AgCl (molar mass = 143.5 g mol^(-1) ). The formula of the complex is (At. mass of Ag = 108 u)

A solution containing 2.675g of COCl_(3).6NH_(3) (molar mass =267.5gmol^(-1) ) is passed through a cation exchanger, The chloride ions obtined in solution were treated with excess of AgNO_(3) to give 4.78g of AgCl ("molar mass" =143.5gmol^(-1) .The formula of the complex is (Atomic mass of Ag=108 u )