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In K4[Fe(CN)6] the EAN of Fe is...

In `K_4[Fe(CN)_6]` the EAN of Fe is

A

33

B

35

C

36

D

26

Text Solution

Verified by Experts

The correct Answer is:
C

Effective atomic number = atomic number – oxidation state + 2 x number of ligands.
` = 26 -2 +2 xx 6 = 36`.
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Knowledge Check

  • In K_4Fe(CN)_6

    A
    (a) `(CN)` is linked with primary valency
    B
    (b) `(CN)` is linked with secondary valency
    C
    (c) K is linked with secondary valency
    D
    (d) K is linked with non-ionic valency
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    B
    complex compound
    C
    neutral molecule
    D
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    (a) An atom
    B
    (b) An ion
    C
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    D
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