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The oxidation number of Cr in [Cr(NH3)6]...

The oxidation number of `Cr` in `[Cr(NH_3)_6]Cl_3` is

A

8

B

6

C

4

D

3

Text Solution

Verified by Experts

The correct Answer is:
D

`x + 6 xx (0) + 3 xx (-1) = 0`
`x -3 = 0, x = + 3` , oxidation number of Cr is = +3
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