The sum of coordination number and oxidation number of the metal M in the complex `[M(en)_2(C_2O_4)]Cl` (where en is ethylenediamine) is:

Options

A. 9
B. 6
C. 7
D. 8

Answer

A

Explanation

(en) and `(C_2O_3^(2-) ) are bidentate. So coordination no. of `M = (2 xx 2) + (1 xx2) = 6`
If oxidation no. Of M in `[M (e n)_2 (C_2O_4)]^(+1) Cl^(-1) ` is x , then :
`x + 2(0) + (-2) = + 1`
x = 3
sum = 6 + 3 = 9