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Considering H2O as a weak field ligand, ...

Considering `H_2O` as a weak field ligand, the number of unpaired electrons in `[Mn(H_2O)_6]^(2+)` will be (At. no. of `Mn=25`)

A

Two

B

Four

C

Three

D

Five

Text Solution

Verified by Experts

The correct Answer is:
D

In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons = 5.
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