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In [Ag(CN)2]^(-), the number of pi bonds...

In `[Ag(CN)_2]^(-)`, the number of `pi` bonds is

A

2

B

3

C

4

D

6

Text Solution

Verified by Experts

The correct Answer is:
C
`[Ag (CN)_2]^- -= [Ag^+ (""^-C -= N)_2]`
Both cyanide ion has one σ and 2π bonds. So no. of π bonds 4 = .
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