Treatment of ammonia with excess of ethyl chloride will yield

Options

A. Diethyl amine
B. Ethane
C. Tetraethyl ammonium chloride
D. Methyl amine

Answer

C

Explanation

`C_2H_5Cl overset(NH_3)(rarr)C_2H_5-NH_2 overset(C_2H_5Cl)(rarr)(C_2H_5)_2-NH overset(C_2H_5Cl)(rarr)(C_2H_5)_3N overset(C_2H_5Cl)(rarr)[C_2H_5-overset(C_2H_5)overset(|)underset("Tetraethyl ammoniumchloride")underset(C_2H_5)underset(|)(N)-C_2H_5]^(+)Cl^(-)`
If `NH_3` is in excess, then `1^@` amine will be the main product, if `C_2H_5Cl` is in excess then mixture of `1^@,2^@,3^@` and quaternary amine is obtained.