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Decreasing order of reactivity in Willia...

Decreasing order of reactivity in Williamson's ether synthesis of the following .
I. `Me_3"CC"H_2Br`
II. `CH_3CH_2CH_2Br`
III. `CH_2=CHCH_2Cl`
IV. `CH_3CH_2CH_2CH_2Cl`

A

III gt II gt IV gt I

B

I gt II gt IV gt III

C

II gt III gt IV gt I

D

I gt III gt II gt IV

Text Solution

Verified by Experts

The correct Answer is:
A
This reaction proceeds by `S_N2` mechanism. The rate of reaction 1° > 2° > 3° alkyl halide Br is better leaving group than Cl and allyl halide is most reactive.
`CH_2=CH-CH_2-Cl>CH_3 -CH_2-CH_2-Br>CH_3-CH_2-CH_2-Cl>(CH_3)_3C-CH_2-Br`.
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Decreasing order of reactivity in Williamson synthesis orf the following . Me_(3)C CH_(2)Br CH_(3)CH_(2)CH_(2)Br CH_(2)=CHCH_(2)CI CH_(3)CH_(2)CH_(2)CI .

The increasing order of reactivity of the following halides for the S_(N)1 reaction is I. CH_(3)CH(CI)CH_(2)CH_(3) II . CH_(3)CH_(2)CH_(2)Cl III. p. -H_(3)CO-C_(6)H_(4)-CH_(2)Cl

Give the order of reactivityh towards SN^(1) reaction of the following: i. ClCH_(2)CH = CH_(2) ii. CH_(3)CH_(2)CH_(2)Cl iii. CH_(3)CH = CHCl

Arrange the following halides in decreasing order of reactivity for Williamson's synthesis : CH_(3)CH_(2)CH_(2)Br,CH_(3)CH_(2)CH_(2)Cl, H_(2)C=CH-CH_(2)Cl,CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(2)Br

Arrange the folliwing compounds in increasing order of SN^(-2) reactivity. a. I.m ClCH_(2)CH = CHCH_(2)CH_(3) II. CH_(3)C(Cl) = CHCH_(2) CH_(3) III. CH_(3)CH = CHCH_(2)CH_(2)Cl IV. CH_(3)CH = CHCH_(2)(Cl) CH_(3) b. I. CH_(3)CH_(2)Br II. CH_(2) = CHCH(Br) CH_(3) III. CH_(2) = CHBr IV. CH_(3)CH (Br) CH_(3) C. I. (CH_(3))_(3)CCl , II. C_(6)H_(5)C(CH_(3))_(2)Cl III. (CH_(3))_(2)CHCl , IV. CH_(3)CH_(2)CH_(2)Cl

Give the decreasing order of reactivity of the following alkyl halides in the Williamson's reaction. i. (CH_(3))_(3)C-CH_(2)Br ii. CICH_(2)CH=CH_(2) iii. (CICH_(2)CH_(2)CH_(3) iv. BrCH_(2)CH_(2)CH_(3)

Arrange the following compounds in decreasing order of their boiling points. (i) CH_3Br CH_3CH_2Br CH_3CH_2CH_2Br CH3CH_2CH_2CH_2Br

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