Following compound are given
1. `CH_3CH_2OH` 2. `CH_3COCH_3`
3. `CH_3- underset(CH_3)underset(|)(CH)OH` 4. `CH_3OH`
Which of the above compound(s), on being warmed with iodine solution and NaOH , will give iodoform

Options

A. 1, 3 and 4
B. Only 2
C. 1, 2 and 3
D. 1 and 2

Explanation

To determine which of the given compounds will give iodoform when warmed with iodine solution and NaOH, we need to identify which of these compounds meet the criteria for the iodoform test. The iodoform test is positive for methyl ketones and for certain alcohols that can be oxidized to methyl ketones.

### Step-by-Step Solution:

1. **Identify the Compounds:**
- Compound 1: `CH₃CH₂OH` (Ethanol)
- Compound 2: `CH₃COCH₃` (Acetone)
- Compound 3: `CH₃C(CH₃)(OH)` (2-Propanol)
- Compound 4: `CH₃OH` (Methanol)

2. **Check Each Compound for Iodoform Test:**
- **Compound 1: Ethanol (`CH₃CH₂OH`)**
- Ethanol is a primary alcohol and does not have the methyl ketone structure. It will not give a positive iodoform test.

- **Compound 2: Acetone (`CH₃COCH₃`)**
- Acetone is a methyl ketone (it has the structure CH₃C(=O)CH₃). It will give a positive iodoform test.

- **Compound 3: 2-Propanol (`CH₃C(CH₃)(OH)`)**
- 2-Propanol can be oxidized to acetone (a methyl ketone). Therefore, it will also give a positive iodoform test.

- **Compound 4: Methanol (`CH₃OH`)**
- Methanol is a primary alcohol and does not have the required structure for the iodoform test. It will not give a positive result.

3. **Conclusion:**
- The compounds that will give iodoform when warmed with iodine solution and NaOH are:
- **Compound 2: Acetone (`CH₃COCH₃`)**
- **Compound 3: 2-Propanol (`CH₃C(CH₃)(OH)`)**

### Final Answer:
The compounds that will give iodoform are **2 (Acetone) and 3 (2-Propanol)**.

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