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Acetyl bromide reacts with excess of CH(...

Acetyl bromide reacts with excess of `CH_(3)MGI` followed by treatement with a saturated solution of `NH_(4)C1` gives:

A

2-methyl-2-propanol

B

Acetamide

C

Acetone

D

Acetyl iodide

Text Solution

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The correct Answer is:
A

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Knowledge Check

  • Acetyl bromide reacts with excess of CH_(3)MgI followed by treatment with a saturated solution of NH_(4)Cl gives :

    A
    acetyl iodide
    B
    acetamide
    C
    `2` - methyl - `2` - propanol
    D
    acetone
  • Acetyl bromide reacts with excess of CH_(3)Mgl followed by treatment with a saturated solution of NH_(4)Cl gives

    A
    2-methyl-2-propanol
    B
    Acetamide
    C
    Acetone
    D
    Acetyl iodide
  • Chlorine reacts with excess NH_3 to give

    A
    `NCl_3`
    B
    HCI
    C
    `N_2`
    D
    `N_2 + NH_4Cl`
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