Which of the following does not give alkane

Options

A. Reaction of `CH_3` I with Na in sodalime
B. Reaction of sodium acetate with sodalime
C. Electrolysis of concentrated sodium acetate solution
D. Reaction of ethyl chloride with alco. KOH

Explanation

To solve the question "Which of the following does not give alkane?", we will analyze each of the given reactions step by step.

### Step 1: Analyze the first reaction (Methyl iodide with sodium in soda lime)
- **Reaction**: 2 CH3I + 2 Na → C2H6 (Ethane) + 2 NaI
- **Explanation**: Methyl iodide (CH3I) reacts with sodium in the presence of soda lime to produce ethane (C2H6). This is a Wurtz reaction, which typically yields alkanes.

### Step 2: Analyze the second reaction (Sodium acetate with soda lime)
- **Reaction**: CH3COONa + NaOH (soda lime) → CH4 (Methane) + Na2CO3
- **Explanation**: Sodium acetate undergoes decarboxylation in the presence of soda lime, resulting in the formation of methane (CH4), which is also an alkane.

### Step 3: Analyze the third reaction (Electrolysis of concentrated sodium ester solution)
- **Reaction**: RCOONa (sodium ester) → R-R + CO2 + NaOH
- **Explanation**: The electrolysis of sodium esters leads to the formation of alkanes through the Kolbe electrolysis process. For example, the electrolysis of sodium acetate can yield ethane (C2H6).

### Step 4: Analyze the fourth reaction (Ethyl chloride with alcoholic KOH)
- **Reaction**: C2H5Cl + KOH (alcoholic) → C2H4 (Ethene) + KCl + H2O
- **Explanation**: Ethyl chloride reacts with alcoholic KOH to undergo elimination, producing ethene (C2H4), which is an alkene, not an alkane.

### Conclusion:
After analyzing all the reactions, we find that the fourth reaction (ethyl chloride with alcoholic KOH) does not produce an alkane; instead, it produces an alkene (ethene).

### Final Answer:
The reaction that does not give an alkane is the fourth one: Ethyl chloride with alcoholic KOH.

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