`C_(2)H_(5)I overset([H]) rarr A. A is `

Options

A. Ethane
B. Butane
C. Methane
D. Methyl iodide

Explanation

To solve the question, we need to analyze the reaction of C₂H₅I (ethyl iodide) when it undergoes reduction.

### Step-by-step Solution:

1. **Identify the Reactant**: The reactant given is C₂H₅I, which is known as ethyl iodide.

2. **Understand the Reaction**: The reaction indicates that ethyl iodide is being reduced. The symbol [H] signifies the addition of hydrogen, which is a common method of reduction.

3. **Reduction Process**: In the presence of a reducing agent, ethyl iodide will gain hydrogen atoms. A common reducing agent used in organic chemistry is zinc (Zn) in the presence of hydrochloric acid (HCl).

4. **Determine the Product**: When ethyl iodide (C₂H₅I) is reduced by the addition of hydrogen, it will lose the iodine atom and gain hydrogen atoms, resulting in the formation of ethane (C₂H₆).

5. **Final Product**: Therefore, the final product A after the reduction of C₂H₅I is ethane (C₂H₆).

### Conclusion:
The product A is ethane (C₂H₆).