`CH_(3) - CH_(2) - CH_(2) - CH_(3) overset(AlCl_3) underset(HBr) rarr ` Product. Product in above reaction is

Options

A. `CH_(3) - underset(Br) underset(|)CH-CH_(2) - CH_(3)`
B. `CH_(3) - underset(CH_3)underset(|)CH - CH_(3)`
C. `underset(Br)underset(|)(CH_2)-CH_(2) - underset(CH_3)underset(|)CH_(2)`
D. All of these

Explanation

To solve the given reaction of butane (CH₃-CH₂-CH₂-CH₃) with AlCl₃ and HBr, we need to analyze the reaction step by step.

### Step 1: Identify the Reactants
The reactant is butane, which has the molecular formula C₄H₁₀. The structure can be represented as:
\[ \text{CH}_3-\text{CH}_2-\text{CH}_2-\text{CH}_3 \]

### Step 2: Understand the Role of AlCl₃
AlCl₃ is a Lewis acid that can facilitate the formation of a carbocation by interacting with the alkane. In this case, it helps in the activation of HBr to generate a more reactive species.

### Step 3: Addition of HBr
When HBr is added to butane in the presence of AlCl₃, it can lead to the formation of a carbocation. The hydrogen from HBr can add to one of the carbon atoms, and the bromine can attach to the adjacent carbon.

### Step 4: Carbocation Formation
The addition of HBr can lead to the formation of a secondary carbocation (more stable than a primary carbocation) if the hydrogen adds to the terminal carbon. The possible carbocations formed can be:
1. CH₃-CH₂-CH₂-CH₂⁺ (primary)
2. CH₃-CH₂-CH⁺-CH₃ (secondary)

### Step 5: Rearrangement and Product Formation
Due to the stability of the secondary carbocation, it is more favorable for the reaction to proceed through this pathway. The bromine ion (Br⁻) will then attack the carbocation, leading to the formation of 2-bromobutane.

### Step 6: Final Product
The final product of the reaction is 2-bromobutane, which can be represented as:
\[ \text{CH}_3-\text{CH}(\text{Br})-\text{CH}_2-\text{CH}_3 \]

### Summary of the Reaction
The reaction can be summarized as:
\[ \text{CH}_3-\text{CH}_2-\text{CH}_2-\text{CH}_3 \overset{\text{AlCl}_3}{\underset{\text{HBr}}{\rightarrow}} \text{CH}_3-\text{CH}(\text{Br})-\text{CH}_2-\text{CH}_3 \]

### Final Answer
The product of the reaction is 2-bromobutane.

---