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The compounds that will give an isomer o...

The compounds that will give an isomer of 2, 2-dimethyl propane on catalytic hydrogenation are
(1) `CH_(3)CH = underset(CH_3)underset(|)C-CH_(3)`
(2) `CH_(3)CH = CHCH_(3)`
(3) `CH_(3)overset(H)overset(|)C= CHCH_(2)CH_(3)`
(4) `CH_(3)underset(CH_(3))underset(|)C = underset(CH_(3))underset(CH_3)C- CH_(3)`

A

1 and 4

B

2 and 4

C

1 and 3

D

1 and 2

Text Solution

AI Generated Solution

The correct Answer is:
To determine which compounds will yield an isomer of 2,2-dimethylpropane upon catalytic hydrogenation, we need to analyze each given compound. ### Step-by-step Solution: 1. **Identify the structure of 2,2-dimethylpropane**: - The molecular formula for 2,2-dimethylpropane is C5H12. It has a central carbon (C) bonded to two methyl groups (CH3) and two other carbons, making it a branched alkane. 2. **Analyze each compound**: - **(1) `CH3CH = CH(CH3)CH3`**: - This compound is 2-methylbut-2-ene. Upon catalytic hydrogenation, the double bond will be converted to a single bond, resulting in 2,2-dimethylpropane (C5H12). - **(2) `CH3CH = CHCH3`**: - This compound is but-2-ene. Upon hydrogenation, it will yield butane (C4H10), which is not an isomer of 2,2-dimethylpropane. - **(3) `CH3C(H)=CHCH2CH3`**: - This compound is 3-methyl-1-pentene. Upon hydrogenation, it will yield 2,2-dimethylpropane (C5H12) as well. - **(4) `CH3(CH3)C=CH(CH3)C-CH3`**: - This compound is 2,3-dimethylbut-2-ene. Upon hydrogenation, it will yield 2,2-dimethylpropane (C5H12) as well. 3. **Conclusion**: - The compounds that will yield an isomer of 2,2-dimethylpropane upon catalytic hydrogenation are (1), (3), and (4). ### Final Answer: The correct options are (1), (3), and (4). ---

To determine which compounds will yield an isomer of 2,2-dimethylpropane upon catalytic hydrogenation, we need to analyze each given compound. ### Step-by-step Solution: 1. **Identify the structure of 2,2-dimethylpropane**: - The molecular formula for 2,2-dimethylpropane is C5H12. It has a central carbon (C) bonded to two methyl groups (CH3) and two other carbons, making it a branched alkane. 2. **Analyze each compound**: ...
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CH_(3)-underset(CH_(3))underset(|)(C)=CH-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-CH_(3)

CH_(3)-CH_(2)-underset(CH_(3))underset(|)(CH)-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(C)-CH_(2)OH

CH_(3)-underset(Cl)underset(|)(C )H-underset(I)underset(|)(C )H-CH_(3) CH_(3)-underset(CH_(3))underset(|)(C)H-(CH_(2))_(4)-underset(CH_(3))underset(|)(C )H-underset(Br)underset(|)(C )H-CH_(2)CH_(3)

Write its IUPAC name CH_(3)-underset(CH_(3))underset(|)(CH)-CH_(2)-underset(CH_(2))underset(|)overset(CH_(3))overset(|)(C)-CH_(3)

The IUPAC name of CH_(3)-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(C)-underset(CH_(3))underset(|)(CH)-underset(I)underset(|)(CH)-CH_(2)-CH_(3) is:

CH_(3)-CH_(2)-CH_(2)-underset(OH)underset(|)(C )H-CH_(3) and CH_(3)-CH_(2)-underset(OH)underset(|)(C )H-CH_(2)-CH_(2)-CH_(3) are

CH_(3)-underset(CH_(3))underset(|)(CH)-CH=CH-CH_(2)-overset(O)overset(||)(C)-OH

The IUPAC name for CH_(3) - underset(OH)underset(|)(CH) - CH_(2) - underset(OH)underset(|)overset(CH_(3))overset(|)(C) - CH_(3) is:

Among these chain isomers are : (I) CH_(3)-CH_(3)-CH_(2)-CH_(2)-OH (II) CH_(3)-CH_(2)-underset(OH)underset(|)(CH)-CH_(3) (III) CH_(3)-underset(CH_(3))underset(|)overset(OH)overset(|)(C)-CH_(3)

The IUPAC name of the compound CH_(3)-underset(CH_(3))underset(|)(C)-underset(CH_(2))underset(||)(C)-CH_(2)-CH_(3) is

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