`CH_(3)-CH - CH_(2) + HBr rarr..........,` the product formed is

Options

A. `CH_(3)- CH_(2) - CH_(2) - Br`
B. `CH_(3) - CHBr - CH_(3)`
C. `BrCH_(2) - CH = CH_(2)`
D. `CH_(2) = C = CH_2`

Explanation

To solve the reaction of propene (CH₃-CH=CH₂) with HBr, we will follow the Markovnikov's rule. Here’s a step-by-step breakdown of the process:

### Step 1: Identify the Reactants
The reactant is propene (CH₃-CH=CH₂) and HBr. Propene is an alkene with a double bond between the second and third carbon atoms.

### Step 2: Understand Markovnikov's Rule
Markovnikov's rule states that when HX (where X is a halogen) adds to an alkene, the hydrogen atom (H) will attach to the carbon with the greater number of hydrogen atoms already attached, while the halide (Br in this case) will attach to the carbon with fewer hydrogen atoms.

### Step 3: Analyze the Structure of Propene
In propene:
- The first carbon (C1) has three hydrogen atoms (CH₃-).
- The second carbon (C2) has one hydrogen atom (CH).
- The third carbon (C3) has two hydrogen atoms (CH₂).

### Step 4: Apply Markovnikov's Rule
According to Markovnikov's rule:
- The hydrogen (H) from HBr will add to the carbon with more hydrogen atoms, which is C1.
- The bromine (Br) will add to the carbon with fewer hydrogen atoms, which is C2.

### Step 5: Write the Product
After the addition of HBr to propene, the product formed will be:
- The structure will be CH₃-CH(Br)-CH₃, which is 2-bromopropane.

### Final Product
The product formed from the reaction of propene with HBr is **2-bromopropane (CH₃-CH(Br)-CH₃)**.

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