In the following reaction
`2CH_(2) = CH_(2) + S_(2)Cl_(2) rarr` Product. The product is

Options

A. Mustard gas
B. Lewisite
C. Polythene
D. Teflon

Explanation

To determine the product of the reaction between 2CH₂=CH₂ (ethylene) and S₂Cl₂ (disulfur dichloride), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in the reaction are:
- Ethylene (CH₂=CH₂)
- Disulfur dichloride (S₂Cl₂)

### Step 2: Understand the Reaction Type
This reaction is an addition reaction where the double bond in ethylene will react with S₂Cl₂. The double bond in alkenes is reactive and can undergo addition reactions with various reagents.

### Step 3: Predict the Product
When ethylene reacts with disulfur dichloride, the sulfur atoms and chlorine atoms will add across the double bond. The expected product will involve the addition of sulfur and chlorine to the carbon atoms of the ethylene.

### Step 4: Write the Product Structure
The product formed from the addition of S₂Cl₂ to ethylene can be represented as follows:
- Each carbon atom of the double bond will bond to one sulfur atom and one chlorine atom.
- The resulting product will be a compound where each carbon is bonded to a sulfur atom and a chlorine atom.

The structure of the product can be represented as:
- CH₂(S)CH(S)Cl

### Step 5: Finalize the Product
The final product can be summarized as:
- The product is 1,2-dichloroethane with sulfur atoms, which can also be referred to as mustard gas (though the term is often used for a different compound, it is important to note that the structure resembles that of mustard gas).

### Conclusion
The product of the reaction `2CH₂=CH₂ + S₂Cl₂` is:
- **CH₂Cl-CH₂S**