Reaction of `Br_2` on ethylene in presence of NaCl gives

Options

A. `BrCH_(2) - CH_(2)Br`
B. `ClCH_(2) - CH_(2)Br`
C. Both (a) and (b)
D. None of these

Answer

C

Explanation

`CH_(2)=CH_(2) + Br_(2) overset(NaCl) rarr underset("1,2-dibromo ethan")underset(Br" " Br)underset(|" "|)(CH_2-CH_2)`
`{:(" "2" "1),(+CH_2-CH_2),(" "|" "|),(Cl" " Br),("1-bromo-2-chloroethane"):}`