`CH_(2) = CH_(2) overset(Br_(2)//H_(2)O) rarr A,`
In the above reaction the compound A is

Options

A. Ethylene bromohydrin
B. 1, 2-dibromo ethane
C. Ethanol
D. None of these

Explanation

To determine the compound A formed from the reaction of ethylene (CH₂=CH₂) with bromine water (Br₂/H₂O), we can follow these steps:

### Step 1: Identify the Reactants
The reactants are ethylene (CH₂=CH₂) and bromine water (Br₂ in the presence of H₂O).

### Step 2: Understand the Reaction Mechanism
The reaction involves the addition of bromine (Br₂) and water (H₂O) across the double bond of ethylene. This is an electrophilic addition reaction.

### Step 3: Electrophilic Attack
In the presence of Br₂, the double bond in ethylene acts as a nucleophile and attacks one of the bromine atoms, leading to the formation of a bromonium ion intermediate. This intermediate is a three-membered ring structure where one bromine atom is positively charged.

### Step 4: Nucleophilic Attack by Water
Water (H₂O) acts as a nucleophile and attacks the more substituted carbon of the bromonium ion. This results in the opening of the bromonium ion and the formation of a product.

### Step 5: Final Product Formation
The final product will have a bromine atom (Br) and a hydroxyl group (OH) added to the two carbon atoms of the original double bond. The product formed is 1-bromo-2-hydroxyethane.

### Step 6: Write the Structure of Compound A
The structure of compound A can be represented as:
- CH₂(OH)-CH₂(Br)

Thus, the compound A is 1-bromo-2-hydroxyethane.

### Final Answer
The compound A is 1-bromo-2-hydroxyethane.

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