The major product obtained in the reaction of toluene with 1 - bromo-2-methyl propane in the presence of anhydrous `AlCl_3` is

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Explanation

To determine the major product obtained from the reaction of toluene with 1-bromo-2-methylpropane in the presence of anhydrous AlCl3, we can follow these steps:

### Step 1: Identify the Reactants
- **Toluene (C6H5CH3)** is the aromatic compound that will undergo electrophilic substitution.
- **1-bromo-2-methylpropane (C5H11Br)** is the alkyl halide that will provide the alkyl group.

### Step 2: Understand the Role of AlCl3
- Anhydrous AlCl3 acts as a Lewis acid and helps in generating a more reactive electrophile from the alkyl halide. In this case, it will facilitate the formation of a carbocation from 1-bromo-2-methylpropane.

### Step 3: Carbocation Formation
- The reaction of 1-bromo-2-methylpropane with AlCl3 leads to the formation of a carbocation. The most stable carbocation that can be formed from 1-bromo-2-methylpropane is the tertiary carbocation, which is formed by the loss of bromide ion (Br-) and the rearrangement of the molecule.

### Step 4: Electrophilic Substitution
- The generated carbocation will then act as an electrophile and will react with the toluene. The electrophilic substitution will occur at the ortho or para position of the aromatic ring due to the electron-donating effect of the methyl group in toluene.

### Step 5: Determine the Major Product
- In this reaction, the major product will be the one formed at the para position due to steric hindrance at the ortho position. Therefore, the major product will be para-alkylated toluene.

### Final Product
- The major product obtained from the reaction is **para-isopropyltoluene** (C6H4(CH(CH3)2)CH3).

### Summary
The major product obtained in the reaction of toluene with 1-bromo-2-methylpropane in the presence of anhydrous AlCl3 is para-isopropyltoluene.

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