Reaction of HBr with propene in the presence of peroxide gives :-

Options

A. Allyl bromide
B. n-propyl bromide
C. Isopropyl bromide
D. 3-bromo propane

Answer

B

Explanation

The formation of n-propyl bromide in presence of peroxide can be explained as follows.
Step-1: Peroxide undergo fission to give free radicals
`R-O - O - R rarr 2 - R - O`
Step-2 : HBr combines with free radical to form bromine free radical `R-O + HBr rarr R - OH + Br`
Step-3 : Br attacks the double bond of the alkene to form a more stable free radical

Step-4 : More stable free radical attacks the HBr
`CH_3 - CH-CH_(2) - Br + HBr rarr underset("n-propyl bromide")(CH_3 CH_2 CH_2Br +Br)`
Step -5 : `Boverset(.)(r) + Boverset(r) rarr Br_(2).`