An alkene "A" on reaction with `O_3` and Zn gives propanone and ethanol in equimolar Addition of HCl to alkene "A" gives "B" as the product. The structure of product "B" is:

Options

A. `H_(3)C-underset(Cl)underset(|)CH-overset(CH_3)overset(|)underset(CH_3)underset(|)CH`
B. `Cl-CH_(2)-CH_(2)- overset(CH_3)overset(|)underset(CH_3)underset(|)CH`
C. `H_(3)C-CH_(2)-overset(CH_2Cl)underset(|)CH-CH_(3)`
D. `H_(3)C-CH_(2)- overset(CH_3)overset(|)underset(Cl)underset(|)C-CH_(3)`

Answer

D

Explanation

Branched hydrocarbons are more desirable because they are more volatile and have high octane number