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In the reaction HC -= CH underse...

In the reaction
` HC -= CH underset( "dil" H_2 SO_4 ) overset( Hg SO_4) to X overset(LIAIH _4 ) to Y overset(P, Br_2) to Z,` Z is

A

Ethylene bromide

B

Ethanol

C

Ethyl bromide

D

Ethylidene bromide

Text Solution

Verified by Experts

The correct Answer is:
C
`CH=CH overset(H_2O //Hg^(2+))underset(H_2SO_4)rarrH_3C-overset(O)overset(||)underset(X)C-H overset(LiAlH_4)rarr`
`CH_(3)-underset((Y))(CH_2)-OH overset(P_4//Br_2) rarr underset((Z))(C_2H_5Br)`
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In the reaction : HC -= CH overset(NaNH_(2)) to overset(CH_(3)I)to Y underset(H^(+))overset(H_(2)O, HG^(2+))to Z ,

(A)underset("dil."H_(2)SO_(4))overset(HgSO_(4))(to)(B)overset(LiAlH_(4))(to) underset("recemic mixture")((C)) therefore reactant (A) is :

CH-=CH underset(dil.H_(2)SO_(4))overset(Hg^(2+))toAunderset(HCl)overset(Zn-Hg)toB B is

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