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On passing a current through molten KCl ...

On passing a current through molten `KCl 19.5` g of K is deposited. The amount of `Al` deposited by the same quantity of electricity if passed through molten `AlCl_(3)` is

A

4.5 g

B

9.0g

C

13.5 g

D

27 g

Text Solution

Verified by Experts

The correct Answer is:
A
`(W_1)/(W_2)=(E_1)/(E_2)rArr(19.5)/(W_2)=(39//1)/(27//3)`
`W_2=4.5g`
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