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A current of strength 2.5 A was passed ...

A current of strength ` 2.5 A` was passed through ` CuSO_4` solution for 6 minute `265` seconds. The amount of copper deposited is (At. Of ` Cu = 63. 5, 1 F = 96500 C`) .

A

0.3175 g

B

3.175 g

C

0.635 g

D

6.35 g

Text Solution

Verified by Experts

The correct Answer is:
A
`Q = 2.5 xx 386 = 96500 C`
`2F (2 xx 96500 C)` deposited Cu = 63.5 g
`therefore` Hence, 965C will be deposited Cu = 0.3175 g
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