The same current if passed through solution of silver nitrate and cupric salt connected in series. If the weights of silver deposited is `1.08g`. Calculate the weight of copper deposited

Options

A. 0.3175 g
B. 3.175 g
C. 0.635 g
D. 6.35 g

Answer

C

Explanation

`("Wt of Cu")/("Wt of Ag") = ("Eq.wt of Cu")/("Eq. wt of Ag"):("wt of Cu")/("Eq. wt of Ag") : ("Wt of Cu")/1.08 = (63.5//2)/108`
Wt. of Cu = 0.3177 g