A current of 10.0A is passed through 1.0L of 1.0M HCl solution for 965 seconds, pH of the solution at the end of the experiment is:-

Options

A. 0
B. 0.2
C. 0.8
D. None of the above

Answer

D

Explanation

`HCl(aq) (1.0 M) to H^(+) (aq) (1 M) + Cl^(-) (aq) (1 M)`
`H^(+)(aq)(1 M) + e^(-) to 1/2 H_(2) (g)`
`pH = - log[H^(+)] = - log (9//10)`
`= log (10//9) 1- log9 = 0.046`