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Given l//a=0.5 cm^(-1), R= 50 "ohm", N= ...

Given `l//a=0.5 cm^(-1), R= 50 "ohm", N= 1.0.` The equivalent conductance of the electrolytic cell is .

A

`10 "ohm"^(-1) "cm"^(3) g eq^(-1)`

B

`20 "ohm"^(-1) cm^(2) g eq^(-1)`

C

`300 "ohm"^(-1) cm^(2) g "eq"^(-1)`

D

`100 "ohm"^(-1) cm^(2) g "eq"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`I//a = 0.5 cm^(-1), R = 50` ohm
`p = (Ra)/l = 50/0.5 = 100`
`Lambda = k xx 1000/N = 1/p xx 1000/N = 1/100 xx 1000/1`
`= 10 "ohm"^(-1) cm^(2) g "eq"^(-1)`
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